Skip to the content

Topics Covered

Types of Reasoning Number Series Letter Series Coding and Decoding Blood Relations and Directions Fractions Time and Distance Ratio, Proportion and Percentage Profit and Loss Interest and Discounting Averages

Topic Overview — What & Why

Unit V is the arithmetic and pattern-finding unit. Nothing here is beyond school mathematics; what the paper tests is speed and care. Most questions can be solved in under a minute with the right shortcut, and most wrong options are the answers a hurried candidate gets: the simple average where a weighted one was needed, simple interest where compound was asked, a percentage of the wrong base.

  • Reasoning is deductive (certain), inductive (probable), abductive (the best explanation) or analogical.
  • Series: find the rule (differences, ratios, squares, alternation), then apply it once more.
  • Codes and relationships: a letter-shift or a pattern; a family tree drawn on paper; directions drawn as a sketch.
  • Aptitude: a small set of formulas, each worked below, and the habit of checking the base of every percentage.

1. Types of Reasoning

TypeMoves fromConclusionExample
DeductiveGeneral premises to a particular conclusionCertain, if the premises are true and the form is validAll metals conduct electricity; copper is a metal; so copper conducts electricity
InductiveParticular observations to a general conclusionProbable; more cases make it stronger, never certainEvery crow seen so far is black; so all crows are black
AbductiveAn observation to its most likely explanationA plausible hypothesis, to be tested (C. S. Peirce's term)The grass is wet this morning; the likeliest explanation is that it rained overnight
AnalogicalA likeness between two casesWhat holds of one probably holds of the otherA drug that lowers blood pressure in rats may do so in humans

Two more terms the paper uses: mathematical reasoning proves results by deduction from axioms (and by mathematical induction, which, despite its name, is a deductive proof); statistical reasoning is inductive, drawing conclusions about a population from a sample, with a stated uncertainty.

EXAMPLE 1 "The sum of the first n odd numbers is n²: it holds for n = 1, and if it holds for n it holds for n + 1." This is proof by mathematical induction, and the conclusion is certain: deductive reasoning.
EXAMPLE 2 "In a survey of 1,000 voters, 54% favoured the proposal, so about 54% of all voters do." This is inductive (statistical) reasoning; its conclusion is probable, with a margin of error.

2. Number Series and Letter Series

Find the rule, test it on every term given, then apply it once more. Try these in order:

  1. Differences between terms: constant (arithmetic), or themselves in a pattern (2, 4, 6, …).
  2. Ratios: constant (geometric), or ×2, ×3, ….
  3. Squares, cubes and primes: 1, 4, 9, 16; 1, 8, 27, 64; 2, 3, 5, 7, 11.
  4. Mixed operations: ×2 + 1; ×3 − 1.
  5. Two series interleaved: the odd-placed and even-placed terms follow different rules.
EXAMPLE 1 2, 6, 12, 20, 30, ? — the differences are 4, 6, 8, 10, so the next difference is 12 and the next term 42. (The terms are also 1×2, 2×3, 3×4, 4×5, 5×6, and 6×7 = 42.)
EXAMPLE 2 3, 7, 15, 31, 63, ? — each term is twice the last plus one: 63×2 + 1 = 127.

Letter series

Number the alphabet A = 1 to Z = 26 and work with the numbers. Useful anchors: E = 5, J = 10, O = 15, T = 20, Y = 25 ("EJOTY"). The reverse position of a letter is 27 minus its position (A ↔ Z, B ↔ Y, M ↔ N).

EXAMPLE 3 B, E, H, K, ? — positions 2, 5, 8, 11: add 3 each time, so 14 = N.
EXAMPLE 4 AZ, BY, CX, ? — the first letters go forward from A, the second back from Z, each pair adding to 27: the next pair is DW.

3. Codes and Relationships

Coding and decoding

A word is coded by a rule: each letter moved forward or back by a fixed number, letters replaced by their reverse, the word written backwards, or letters replaced by numbers. Find the rule from the given pair, then apply it.

EXAMPLE 1 If CAT is coded DBU, each letter moves forward by 1. So DOG is coded EPH.
EXAMPLE 2 If each letter is replaced by its position, BAD = 2 + 1 + 4 = 7 when the code is the sum. Then CAB = 3 + 1 + 2 = 6.

Blood relations

Draw the family tree: one generation per row, men and women marked, marriages with a double line. Read the relationship from the speaker's point of view.

EXAMPLE 3 Pointing to a man, Meena says, "He is the son of my grandfather's only son." Her grandfather's only son is her father, and his son is her brother.

Directions

Sketch every move. For distance from the start, use Pythagoras on the net north–south and east–west movement. Turning right from north faces east; turning left from north faces west.

EXAMPLE 4 A man walks 3 km north, then 4 km east. He is √(3² + 4²) = 5 km from the start, to the north-east.

4. Mathematical Aptitude

Fractions

To compare fractions, put them over a common denominator, or turn them into decimals. 3/5 = 0.6 and 5/8 = 0.625, so 5/8 is larger. The sum 1/2 + 1/3 = 3/6 + 2/6 = 5/6.

Time and distance

EXAMPLE 1 A car goes from A to B at 40 km/h and returns at 60 km/h. Average speed = 2 × 40 × 60 ÷ (40 + 60) = 4,800 ÷ 100 = 48 km/h, not 50.
EXAMPLE 2 A train 150 m long at 54 km/h (= 15 m/s) passes a platform 300 m long in (150 + 300) ÷ 15 = 30 seconds.

Ratio, proportion and percentage

Profit and loss

EXAMPLE 3 An article bought for ₹400 is sold for ₹500. Profit = ₹100, and profit % = 100/400 × 100 = 25%.
EXAMPLE 4 A shopkeeper marks a shirt at ₹800 and gives a 10% discount. Selling price = 800 × 0.9 = ₹720. If it cost ₹600, the profit is ₹120, which is 20% of cost.

Interest and discounting

EXAMPLE 5 ₹10,000 for 2 years at 10%: SI = 10,000 × 10 × 2 ÷ 100 = ₹2,000. Amount at compound interest = 10,000 × 1.1² = ₹12,100, so CI = ₹2,100. The difference, ₹100, equals 10,000 × (0.1)².
EXAMPLE 6 The present value of ₹11,000 due in one year at 10% is 11,000 ÷ 1.1 = ₹10,000; the true discount is ₹1,000.

Averages

EXAMPLE 7 Five numbers average 20. One is removed and the other four average 18. The removed number is 5 × 20 − 4 × 18 = 100 − 72 = 28.
EXAMPLE 8 A class has 30 boys averaging 60 marks and 20 girls averaging 70. The class average is (30 × 60 + 20 × 70) ÷ 50 = (1,800 + 1,400) ÷ 50 = 64, not 65.
Exam pointers for Unit V.
  • Average speed over equal distances: 2xy ÷ (x + y), never (x + y) ÷ 2.
  • km/h × 5/18 = m/s.
  • Successive changes: a + b + ab/100. Equal rise and fall always leave a net fall.
  • Profit % is on cost; discount % is on the marked price.
  • For two years, CI − SI = P(R/100)².
  • Averages: work with sums. Weighted averages: weight by group size.
  • Letters: EJOTY = 5, 10, 15, 20, 25; reverse position = 27 − position.

Final Revision Checklist